17x^2=160

Solution for 17x^2=160 equation:

17x^2=160

We move all terms to the left:

17x^2-(160)=0

a = 17; b = 0; c = -160;
Δ = b2-4ac
Δ = 02-4·17·(-160)
Δ = 10880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10880}=\sqrt{64*170}=\sqrt{64}*\sqrt{170}=8\sqrt{170}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{170}}{2*17}=\frac{0-8\sqrt{170}}{34}
=-\frac{8\sqrt{170}}{34}
=-\frac{4\sqrt{170}}{17}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{170}}{2*17}=\frac{0+8\sqrt{170}}{34}
=\frac{8\sqrt{170}}{34}
=\frac{4\sqrt{170}}{17}
$